a)

b)

c)

a) $\frac{16}{2^n}=\mathrm{2\; =>\; \backslash (\backslash dfrac\{2^4\}\{2^n\}=2\backslash Rightarrow2^\{4-n\}=2\backslash Rightarrow4-n=1\backslash Rightarrow\; n=3\backslash )}$

b,
\(\dfrac{\left(-3\right)^n}{81}=-27\Rightarrow\dfrac{\left(-3\right)^n}{\left(-3\right)^4}=-27\Rightarrow\left(-3\right)^{n-4}=\left(-3\right)^3\Rightarrow n-4=3\Rightarrow n=7\)

c,\(8^n:2^n=4\Rightarrow4^n=4\Rightarrow n=1\)

=> (-3)n-4 = (-3)3

=> n - 4 = 3 => n = 7

c) 8n : 2n = 4

4n = 4.

a, 16/2n=2

<=>2n=8

<=>n=4

b, (-3)^n =-27*81=-2187

n=7( vì (-3)^7 =-2187

c, 8^n : 2^n =4

<=> (8:2)^n=4

4^n=4

n=1

\(a,\frac{16}{2^n}=2=>\frac{2^4}{2^n}=2=>2^4:2^n=2=>2^{4-n}=2=>4-n=1=>n=3\)

\(b,\frac{\left(-3\right)^n}{81}=-27=>\frac{\left(-3\right)^n}{3^4}=\left(-3\right)^3=>\frac{\left(-3\right)^n}{\left(-3\right)^4}=\left(-3\right)^3=>\left(-3\right)^{n-4}=\left(-3\right)^3=>n-4=3=>n=7\)

\(c,8^n:2^n=4=>\left(8:2\right)^n=4=>4^n=4=>n=1\)

a)

\(\frac{16}{2^x}=2\)

\(\Rightarrow2^{x+1}=16\)

\(\Rightarrow2^{x+1}=2^4\)

\(\Rightarrow x+1=4\)

\(\Rightarrow x=3\)

b)

\(\frac{\left(-3\right)^x}{81}=-27\)

\(\Rightarrow\left(-3\right)^x=-\left(3^3.3^4\right)\)

\(\Rightarrow-3^x=-3^7\)

=> x=7

c)

\(8^n:2^n=4\)

\(\Rightarrow2^{3n}:2^n=4\)

\(\Rightarrow2^{3n-n}=4\)

\(\Rightarrow2^{2n}=2^2\)

=>2n=2

=>n=1

a) \(\frac{16}{2^n}=2\Rightarrow2^nx2=16\)

\(\Rightarrow2^n=16:2=8=2^3\)

\(\Rightarrow n=3\)

b) \(\frac{\left(-3\right)^n}{81}=-27\Rightarrow\left(-3\right)^n=\left(-27\right)x81=-2187\)

\(\Rightarrow\left(-3\right)^n=\left(-3\right)^7\Rightarrow n=7\)

c) \(8^n:2^n=4\Rightarrow\left(2^3\right)^n:2^n=2^2\)

\(\Rightarrow2^{3n}:2^n=2^2\)

\(\Rightarrow3n-n=2\)

\(\Rightarrow2n=2\Rightarrow n=1\)

Chúc bạn học tốt!

a)n=3

b)n=7

c)n=1

mk đã làm r nhé bn

a, \(\dfrac{16}{2^n}=2\)

\(2^n=\dfrac{16}{2}\)

\(2^n=8\)

\(2^n=2^3\)

=> n = 3

b, \(\dfrac{\left(-3\right)^n}{81}=-27\)

\(\left(-3\right)^n=-27\cdot81\)

\(\left(-3\right)^n=\left(-3\right)^3\cdot3^4\)

\(\left(-3\right)^n=\left(-3\right)^7\)

=> n = 7

c, \(8^n:2^n=4\)

\(2^{3n}:2^n=2^2\)

\(2^{2n}=2^2\)

=> 2n = 2

n = 2:2

n = 1

a )

\(\dfrac{16}{2^n}=2\) \(\Leftrightarrow16:x=2\)

\(\Rightarrow x=8\)

\(2^n=8\Rightarrow n=3\)

b )

\(\dfrac{\left(-3\right)^n}{81}=-27\) \(\Leftrightarrow x=-27.81\)

\(\Rightarrow x=-2187\)

\(\left(-3\right)^n=-2187\Rightarrow n=7\)

c )

\(8^n:2^n=4\Leftrightarrow4^n=4\)

\(\Rightarrow n=1\)

(2^2:4)*2^n=4

3^2*3^4*3^n=3^7

a)16/2ⁿ=2

=>16=2ⁿ.2

=>8=2ⁿ

=>2³=2ⁿ

=>n=3

b)(-3)ⁿ/81=-27

<=>(-3)ⁿ=(-27).81

<=>(-3)ⁿ=-2187

<=>(-3)ⁿ=(-3)⁷

<=>n=7

c)8ⁿ:2ⁿ=4

<=>8ⁿ=4.2ⁿ

<=>2³ⁿ=2²⁺ⁿ

<=>3n=2+n

<=>2n=2

<=>n=1

a) \(\frac{16}{2^n}=2\)

=> 2.2ⁿ = 16

=> 2¹⁺ⁿ = 2⁴

=> 1 + n = 4

=> n = 4 - 1

=> n = 3

Vậy n = 3

b) \(\frac{\left(-3\right)^n}{81}=-27\)

=> (-3)ⁿ = -27.81

=> (-3)ⁿ = -3³.3⁴

=> (-3)ⁿ = (-3)⁷

=> n = 7

Vậy n = 7

c) 8ⁿ : 2ⁿ = 4

=> (8 : 2)ⁿ = 4

=> 4ⁿ = 4¹

=> n = 1

Vậy n = 1

\(\frac{16}{2^n}=2\Rightarrow2^n=16:2\Rightarrow2^n=8\Rightarrow n=3\)

\(\frac{\left(-3\right)^n}{81}=-27\Rightarrow\left(-3\right)^n=\left(-27\right).81\Rightarrow\left(-3\right)^n=-2187\Rightarrow n=7\)

\(8^n:2^n=4\Rightarrow\left(8:2\right)^n=4\Rightarrow4^n=4\Rightarrow n=1\)

a) => 2ⁿ = 16/2 = 8

 => n = 3

b) => (-3)ⁿ  = -27 x 81 = -2187

 => n = 7

c) 8ⁿ : 2ⁿ = ( 8 : 2)ⁿ = 4ⁿ = 4

 => n = 1